Diamond da 40 poh

Manuals Brands Diamond Aircraft Manuals Tools DA 42 Flight manual Contents Table of Contents Troubleshooting Bookmarks Quick Links Chapters General 15 Operating Limitations 37 Emergency Procedures 69 A Normal Operating Procedures 125 B Abnormal Operating Procedures 165 Performance 199 Mass and Balance 233 Description of the Airplane and Its Systems 253 Airplane Handling, Care and Maintenance 319 Need help? Do you have a question about the DA 42 and is the answer not in the manual? Questions and answers Related Manuals for Diamond Aircraft DA 42 Summary of Contents for Diamond Aircraft DA 42 Page 2 Introduction DA 42 AFM Intentionally left blank. Page 0 - 0a Rev. 3 15-Oct-2005 Doc. # 7.01.05-E... Page 3 Before this airplane is operated for the first time, the pilot must familiarize himself with the complete contents of this Airplane Flight Manual. In the event that you have obtained your DIAMOND DA 42 second-hand, please let us know your address, so that we can supply you with the publications necessary for the safe operation of your airplane. Page 4 Introduction DA 42 AFM 0.1 APPROVAL The content of approved chapters is approved by EASA. All other content is approved by DAI under the authority of EASA DOA No. EASA.21J.052 in accordance with Part 21. 0.2 RECORD OF REVISIONS All revisions of this manual, with the exception of - •... Page 5 DA 42 AFM Introduction Rev. Chap- Date of Date Reason Page(s) Approval Verification Signature Revision Inserted [Ing. all except cover Andreas certification; 1 Dec 2004 2005-196 page Winkler for corrections ACG] 0-3, 0-5, MÄM 42-034 [10 Feb (elevator 0-7, 0-8, 0-9 2005 stop);... Page 7 DA 42 AFM Introduction 0.3 LIST OF EFFECTIVE PAGES Ch. Page Date Ch. Page Date 15-Oct-2005 29-Apr-2004 30-Nov-2005 0-0a 15-Oct-2005 appr. 2-3 15-Oct-2005 15-Oct-2005 appr. 2-4 30-Nov-2005 15-Oct-2005 appr. 2-5 15-Oct-2005 30-Nov-2005 appr. 2-6 15-Oct-2005 30-Nov-2005 appr. 2-7 30-Nov-2005 30-Nov-2005 appr. Page 8 Introduction DA 42 AFM Ch. Page Date Ch. Page Date 15-Oct-2005 3-31 30-Nov-2005 15-Oct-2005 3-32 30-Nov-2005 15-Oct-2005 3-33 15-Oct-2005 15-Oct-2005 3-34 15-Oct-2005 15-Oct-2005 3-35 15-Oct-2005 15-Oct-2005 3-36 15-Oct-2005 15-Oct-2005 3-37 15-Oct-2005 15-Oct-2005 3-38 30-Nov-2005 15-Oct-2005 3-39 15-Oct-2005 3-10 15-Oct-2005 3-40... Page 9 DA 42 AFM Introduction Ch. Page Date Ch. Page Date 4A-1 30-Nov-2005 4B-1 15-Oct-2005 4A-2 30-Nov-2005 4B-2 30-Nov-2005 4A-3 30-Nov-2005 4B-3 15-Oct-2005 4A-4 30-Nov-2005 4B-4 15-Oct-2005 4A-5 30-Nov-2005 4B-5 15-Oct-2005 4A-6 30-Nov-2005 4B-6 15-Oct-2005 4A-7 30-Nov-2005 4B-7 15-Oct-2005 4A-8 30-Nov-2005... Page 10 Introduction DA 42 AFM Ch. Page Date Ch. Page Date 30-Nov-2005 15-Oct-2005 30-Nov-2005 15-Oct-2005 30-Nov-2005 15-Oct-2005 30-Nov-2005 15-Oct-2005 30-Nov-2005 30-Nov-2005 30-Nov-2005 15-Oct-2005 30-Nov-2005 15-Oct-2005 30-Nov-2005 30-Nov-2005 30-Nov-2005 15-Oct-2005 5-10 30-Nov-2005 6-10 30-Nov-2005 5-11 30-Nov-2005 6-11 30-Nov-2005 5-12 30-Nov-2005 6-12 30-Nov-2005... Page 11 DA 42 AFM Introduction Ch. Page Date Ch. Page

Chemical industry/Shutterstock The pH scale, which ranges from 0 to 14, tells you how acidic or alkaline a solution is. A pH lower than 7 is acidic, while a pH higher than 7 is alkaline. In mathematical terms, pH is the negative logarithm of the molar concentration of hydrogen ions in the solution. A pH testing strip will tell you that NaOH (sodium hydroxide) is a strong alkaline, but to calculate its exact pH, you have to work out its molarity first. Calculating molarity Molarity (M) is the concentration of a solution expressed as the number of moles of solute per liter of solution, using the formula M = moles solute ÷ liters solution. The first step is calculating the number of moles of solute present. If you have dissolved 1 gram of NaOH in enough water to make a total of 250 milliliters of solution, calculate the number of moles of solute present by diving the mass of NaOH by the molecular mass of the compound. The molecular mass of NaOH is 40, so work out 1 ÷ 40 = 0.025.Next, calculate the number of liters of solution present. In this example, you have 250 milliliters of solution. Convert to liters by dividing by 1000, because there are 1000 milliliters in 1 liter. Work out 250 ÷ 1000 = 0.25.Next, divide the number of moles of solute by the number of liters of solution. Work out 0.025 ÷ 0.25 = 0.1. The molarity of the NaOH solution is 0.1 M. Ionization of NaOH Ionization is the addition or removal of an electron to create an ion. Losing an electron creates a positive ion, and gaining an electron creates a negative ion. An aqueous solution of NaOH (NaOH + H2O) results in Na+ and OH- ions. Because NaOH is a strong base, it ionizes completely in water. This means 0.1 mol of it will dissociate into 0.1 mol of Na+ and OH-. Calculating pH To calculate pH, apply the formula pOH = -log[OH-]. Work out -log[0.1] = 1. Next, apply the formula pH + pOH = 14. To isolate the

1. Salt Hydrolysis Key Concepts ● Hydrolysis : The reaction between water and a compound, leads to cleavage of bonds. ● Salts of different combinations of acids and bases behave differently: 1. Strong Acid + Strong Base : No hydrolysis; neutral solution (e.g., NaCl). 2. Weak Acid + Strong Base : Basic solution due to anion acting as a base (e.g., NaCH₃COO). 3. Strong Acid + Weak Base : Acidic solution due to cation acting as an acid (e.g., NH₄Cl). 4. Weak Acid + Weak Base : pH depends on the relative Ka and Kb values. Formulas 1. For a conjugate base of a weak acid: Kb=KwKaK_b = \frac{K_w}{K_a}Kb =Ka Kw Where Kw=1×10−14K_w = 1 \times 10^{-14}Kw =1×10−14 (at 25°C). 2. For pH and pOH calculations: pOH=−log [OH−]\text{pOH} = -\log[OH^-]pOH=−log[OH−] pH=14−pOH\text{pH} = 14 - \text{pOH}pH=14−pOH Steps to Solve Hydrolysis Problems 1. Identify if the salt hydrolyzes: ○ Check if the anion is the conjugate base of a weak acid or if the cation is the conjugate acid of a weak base. ○ Look for small, highly charged metal ions (e.g., Al³⁺, Fe³⁺) that may hydrolyze. 2. Use the appropriate formula to calculate KbK_bKb or KaK_aKa : ○ Example: Kb(CN−)=KwKa(HCN)K_b(\text{CN}^-) = \frac{K_w}{K_a(\text{HCN})}Kb (CN−)=Ka (HCN)Kw . 3. Calculate the pOH using the equilibrium concentration of OH−OH^-OH−. 4. Determine the pH. 2. Buffer Solutions Key Concepts ● A buffer is a solution that resists pH change, typically containing: 1. A weak acid and its conjugate base (e.g., CH₃COOH and CH₃COO⁻). 2. A weak base and its conjugate acid (e.g., NH₃ and NH₄⁺). Henderson-Hasselbalch Equation ● For pH of buffer solutions: pH=pKa+log ([A−][HA])\text{pH} = \text{pKa} + \log \left( \frac{[\text{A}^-]}{[\text{HA}]} \right)pH=pKa+log([HA][A−] ) Where: ○ [A−][\text{A}^-][A−]: Concentration of the conjugate base. ○ [HA][\text{HA}][HA]: Concentration of the weak acid. Steps to Solve Buffer Problems 1. Identify the

(3705) (Refer to Figure 40.) Determine the total distance required for takeoff to clear a 50-ft obstacle.OAT..............................................StdPressure altitude...................4,000 ftTakeoff weight.......................2,800 lbHeadwind component......CalmA- 1,500 ft.B- 1,750 ft.C- 2,000 ft.B- 1,750 ft(See pg. 8-31 in PPTP)(3706) (Refer to Figure 40.) Determine the total distance required for takeoff to clear a 50-ft obstacle.OAT.............................................StdPressure Altitude..................Sea LevelTakeoff Weight......................2,700 lbHeadwind component......CalmA- 1,000 ft. B- 1,400 ft.C- 1,700 ft.B- 1,400 ft(See pg. 8-31 in PPTP)(3707) (Refer to Figure 40.) Determine the approximate ground roll distance required for takeoff.OAT..............................................StdPressure altitude...................2,000 ftTakeoff weight.......................2,750 lbHeadwind component......CalmA- 1,150 ftB- 1,300 ftC- 1,800 ftA- 1,150 ft(See pg. 8-31 in PPTP)(3708) (Refer to Figure 40.) Determine the approximate ground roll distance required for takeoff.OAT............................................95FPressure altitude..................2,000ftTakeoff weight......................2,500 lbHeadwind component.....20 ktsA- 650 ftB- 850 ftC- 1,000 ftA- 650 ft(See pg. 8-32 in PPTP)(2199) What effect does an uphill runway slope have on takeoff performance?A- Increases takeoff speed.B- Increases takeoff distance.C- Decreases takeoff distance.B- Increases takeoff distanceThe effect of runway slope on takeoff distance is due to the component of weight along the inclined path of the aircraft. An upslope would contribute a retarding force component, while a downslope would contribute an accelerating force component. In the case of an upslope, the retarding force component adds to drag and rolling friction to reduce the net accelerating force.(2283) The most critical conditions of takeoff performance are the result of some combination of high gross weight, altitude, temperature, andA- unfavorable wind.B- obstacles surrounding the runway.C- powerplant systems.A- unfavorable windThe most critical conditions of takeoff performance are the result of some combination of high gross weight, altitude, temperature, and unfavorable wind. In all cases, the pilot must make an accurate prediction of takeoff distance from the performance data of the AFM/POH, regardless of the runway available, and strive for a polished, professional takeoff procedure.(2234) The most critical conditions of takeoff performance are the result of some combination of high gross weight, altitude, temperature, andA- unfavorable wind.B- obstacles surrounding the runway.C- powerplant systems.A- unfavorable wind.The most critical conditions of takeoff performance are the result of some combination of high gross weight, altitude, temperature, and unfavorable wind. In all cases, the pilot must make an accurate prediction of takeoff distance from the performance data of the AFM/POH, regardless of the runway available, and strive for a polished, professional takeoff procedure.